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(x+7)^(2)=(x-5)(x+2)
We move all terms to the left:
(x+7)^(2)-((x-5)(x+2))=0
We multiply parentheses ..
-((+x^2+2x-5x-10))+(x+7)^2=0
We calculate terms in parentheses: -((+x^2+2x-5x-10)), so:We get rid of parentheses
(+x^2+2x-5x-10)
We get rid of parentheses
x^2+2x-5x-10
We add all the numbers together, and all the variables
x^2-3x-10
Back to the equation:
-(x^2-3x-10)
-x^2+3x+(x+7)^2+10=0
We add all the numbers together, and all the variables
-1x^2+3x+(x+7)^2+10=0
We move all terms containing x to the left, all other terms to the right
-1x^2+3x+(x+7)^2=-10
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